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 Forum index » DIY Hardware and Software » YuSynth
Clock divider Led resistors
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Satindas



Joined: Mar 26, 2011
Posts: 39
Location: uk

PostPosted: Thu Feb 09, 2012 3:15 pm    Post subject: Clock divider Led resistors Reply with quote  Mark this post and the followings unread

Hi Yves,
Could you tell me which resistors to change for the Clock Divider LED's.
My blue led is soooo bright. Cool

Many thanks
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ungleichklang



Joined: Dec 03, 2011
Posts: 70
Location: East-Belgium

PostPosted: Fri Feb 10, 2012 1:30 pm    Post subject: Reply with quote  Mark this post and the followings unread

I haven't build it, but as far as I can see from the shematics,
the devider has 3 LEDs
they are connected to (R12, R24, R36) 220R resistors.
I think (I am pretty shure) you have to change those Smile

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Satindas



Joined: Mar 26, 2011
Posts: 39
Location: uk

PostPosted: Fri Feb 10, 2012 3:17 pm    Post subject: Reply with quote  Mark this post and the followings unread

ungleichklang wrote:
I haven't build it, but as far as I can see from the shematics,
the devider has 3 LEDs
they are connected to (R12, R24, R36) 220R resistors.
I think (I am pretty shure) you have to change those Smile


Thanks ungleichklang. I was suspecting those resistors but not sure if it could also be down to 13, 25 & 37. Changing either of these two groups would seem to alter the potential divider across the output..
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Mongo1



Joined: Aug 11, 2011
Posts: 411
Location: Raleigh NC

PostPosted: Fri Feb 10, 2012 8:39 pm    Post subject: Reply with quote  Mark this post and the followings unread

Quote:
I was suspecting those resistors but not sure if it could also be down to 13, 25 & 37. Changing either of these two groups would seem to alter the potential divider across the output..


Yes- you're exactly right.

Since you're trying to use those #$S# blue LEDs, it's not unusual to have to use a 10K resistor with them. That will mess things up in this case.

Here's what I think you could try (do it on one of the circuits first to see if this works)

1) Connect the cathode of the blue LED to a 10K resistor to ground.
2) Connect the top side of R12 directly to the emitter of the transistor (pin 7 on the schematic). You should probably increase the size of that resistor until the output level is at 10V (if you have the zener diode in place, this won't matter).

I think that should do the trick. Alternately you could change R12 to 10K, and do some math to work out a new value for R13 that would restore the output level to 10V.

OR you could just use regular LEDs Laughing

Gary
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Satindas



Joined: Mar 26, 2011
Posts: 39
Location: uk

PostPosted: Sat Feb 11, 2012 1:36 am    Post subject: Reply with quote  Mark this post and the followings unread

Thanks Gary. That all makes sense. I think I'll do a quick simulation based on your suggestions (my electronics math is rubbish). Why did I choose blue? For quicker id. I have a different colour led for each output; red, yellow and bue. I'd settle for red,yellow and green but I'm red/green colour blind. colors
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Satindas



Joined: Mar 26, 2011
Posts: 39
Location: uk

PostPosted: Sat Feb 11, 2012 2:11 am    Post subject: Reply with quote  Mark this post and the followings unread

so this is how it looks...

Replace R36 with 470R connected to emitter of Q9 (maintains 10V at output)
Blue led to ground via 3K3 resistor ( 3.54 mA through led = half of original current)

Doing it the other way; subbing a 1K for R36 and 3K for R37 gives 9.48V out and 3.16mA through the led. (good enough for jazz!)

So...Gary I like your idea of a separate ground connection for the led. At least that way if the led fails I still have a clock output.
thanks Gary... Now I can remove my shades
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Mongo1



Joined: Aug 11, 2011
Posts: 411
Location: Raleigh NC

PostPosted: Sat Feb 11, 2012 7:01 am    Post subject: Reply with quote  Mark this post and the followings unread

I'm glad I could help.

BTW - I have one of those modules sitting on my table right now. Still waiting to get built!

I like the idea of using different LED colors for each channel. I think I might do that. Thanks for the idea!


Gary
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