Author |
Message |
triptikon
Joined: Dec 23, 2012 Posts: 2 Location: gent, belgium
|
Posted: Wed Jan 02, 2013 2:05 pm Post subject:
double multiplexer / waveform modeler and envelope generator |
|
|
hello everybody...
i was wondering if the following would work???
a lfo oscillator clocks a ripple counter clocks a multiplexer...
the eight gates of the multiplexer each have a sliding pot/fader, so a variable voltage can obtained at each of the gates...
here we have an envelope generator...
we now take a oscillator much higher frequency, we let it clock a ripple counter, let it clock another multiplexer...
this multiplexor also has eight faders in front of it... the voltage feeding these faders is the voltage coming out of the envelope generator...
here we have a waveform modeler...
nothing new here except for the use of faders... it makes it all a little bit easier to visualize what we're setting up... the waveform we here is exactly the same we see in front of us, dialed in with our faders...
i looked up the prices of faders, they come around 50 cents a piece... but the problem is that they're only available as 10k faders!!! how can i solve this problem... how can i calculate the amount of resistance these faders need to have???
greetings from belgium, ghent!!! |
|
Back to top
|
|
|
elmegil
Joined: Mar 20, 2012 Posts: 2177 Location: Chicago
Audio files: 16
|
Posted: Wed Jan 02, 2013 6:15 pm Post subject:
|
|
|
osc clocking ripple counter clocking mux is the classic CMOS step sequencer. A CD4017 eliminates the middle step by doing the demux onboard.
What I'm not grasping is how you intend the second level to be fed from the first. Can you draw a schematic of your idea?
Re-reading it do you mean that the output voltage of sequencer 1 (slowly clocked) is driving a VCA that has sequencer 2 (fast clocked) as its audio input?
Since this whole scheme really only uses the pots as voltage dividers, the 10K limitation is less about the waveforms than it is about the current draw from the chips driving the two sequencers. current is voltage over resistance, so whatever your max output voltage divided by 10K is the (essentially) current that each fader will draw, and you need to be sure that is less than the max the chip can supply.
And yes, I know my language is somewhat loose here (current draw blah blah), but hopefully my point is clear. |
|
Back to top
|
|
|
triptikon
Joined: Dec 23, 2012 Posts: 2 Location: gent, belgium
|
|
Back to top
|
|
|
|