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| Cynosure Site Admin
 
  
 Joined: Dec 11, 2010
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|  Posted: Thu Nov 10, 2011 7:39 am    Post subject: |    |   
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| Ok.  then maybe I will do this - power the sequencer parts of the lunetta using 0V on the Vss instead of -5. Then I can use the 5V option. |  | 
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| diablojoy 
 
  
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|  Posted: Fri Nov 11, 2011 1:46 am    Post subject: |    |   
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| yes matthias that does sound right was just stressing the importance of not exceeding the rail voltages
 would really help to know the ccts cynosure is driving
 it could be a 4017 based sequencer running on +5/-5 or equally it could be +5 and 0v with the -5v only used elsewhere
 
 
 
  	  | Quote: |  	  | power the sequencer parts of the lunetta using 0V on the Vss instead of -5. Then I can use the 5V option. | 
 
 cynosure if that is possible to do with the particular lunetta sequencer's
 it is not a bad option, though i cant imagine the cct was designed with -5v in mind and there not being a good reason for it [dual rail opamps somewhere ? ] otherwise you could go with a small interface to
 offset the pulse voltage to the correct level as in matthias's option D
 which maybe the better deal and easier
 you could try the M2C with the 5v output first and see if it will clock your lunetta as is , I dont think it would harm anything [ guessing here really ]and if that does not work then tack a small interface cct on the front end of the lunetta to offset the level to -5 low to 0v high
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| fonik 
 
  
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|  Posted: Fri Nov 11, 2011 2:04 am    Post subject: |    |   
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|  	  | Cynosure wrote: |  	  | The CMOS chips run on +5/-5, so the logic signal is a total of 10V. | 
 so Vdd is +5V and Vss is -5V.
 however i have to correct myself. the threshold of i.e. CD4017 would be at approx. +2V then. (High Level Input Voltage is 7V for 10V operation according datasheet).
 so just be sure to not exceed the +5V on the lunetta's input.
 
 sorry for the confusion.
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 matthias
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| diablojoy 
 
  
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|  Posted: Fri Nov 11, 2011 8:24 pm    Post subject: |    |   
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|  	  | Quote: |  	  | however i have to correct myself. the threshold of i.e. CD4017 would be at approx. +2V then. | 
 
 Doh i should have seen that as well
   So the M2C should clock the lunetta fine with its outputs set at +5v
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 In an infinite universe one might very well
 ask where the hell am I
 oh yeah thats right the land of OZ
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| fonik 
 
  
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|  Posted: Sat Nov 12, 2011 7:09 am    Post subject: |    |   
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| cynosure, are you still there?  _________________
 
   cheers,
 matthias
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 Tech Buddy at Random*Source
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| Cynosure Site Admin
 
  
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|  Posted: Sat Nov 12, 2011 10:06 am    Post subject: |    |   
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| Sorry - I was entrapped with soldering a wasp filter (your name on the schematic Matthias, so thanks for that one too). 
 The thing that the clock will actually be triggering is a 4040.  I know the MIDI2CLOCK has a divider in it, but i included one in my sequencer too for use when clocking from other lunetta devices. The output of the 4040 then goes to a 4029, which is decoded using a 4514.
 
 Thanks for the info.  I don't have the MIDI2CLOCK soldered up yet (working on the synth/sequencer it controls first), but I can easily breadboard a 5/0V clock pulse to test it out.
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| fonik 
 
  
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|  Posted: Sat Nov 12, 2011 2:33 pm    Post subject: |    |   
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|  	  | Cynosure wrote: |  	  | ...I can easily breadboard a 5/0V clock pulse to test it out. | 
 yes, this would be good. i wonder if the 0V is low enough for the CMOS powered by -5V/+5V...
 if not you will have to do it the way i recommended: use 0V/10V triggers and move them down to -5V/+5V on the lunetta side.
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 matthias
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| Cynosure Site Admin
 
  
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|  Posted: Sun Dec 18, 2011 8:57 am    Post subject: |    |   
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| FYI.  Now that the cmos synth is done, I have tested it out with a 40106 clock on breadboard using a 9V battery and a 7805. It clocks the sequencer if I add a capacitor to the +5 clock pulse and don't use the clock to also power an led. Maybe a current issue? 
 Anyway, it should work with the 5V option on the midi2clock pcb once I get around to soldering that together. At most, i might need to add a cap on the output.
 
 Thanks for the help!
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